Newcomb’s problem is a thought experiment where you’re presented with two boxes, and the option to take one or both. One box is transparent and always contains $1000. The second is a mystery box.

Before making the choice, a supercomputer (or team of psychologists, etc) predicted whether you would take one box or both. If it predicted you would take both, the mystery box is empty. If it predicted you’d take just the mystery box, then it contains $1,000,000. The predictor rarely makes mistakes.

This problem tends to split people 50-50 with each side thinking the answer is obvious.

An argument for two-boxing is that, once the prediction has been made, your choice no longer influences the outcome. The mystery box already has whatever it has, so there’s no reason to leave the $1000 sitting there.

An argument for one-boxing is that, statistically, one-boxers tend to walk away with more money than two-boxers. It’s unlikely that the computer guessed wrong, so rather than hoping that you can be the rare case where it did, you should assume that whatever you choose is what it predicted.

  • Azzu@lemmy.dbzer0.com
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    2 hours ago

    The answer depends entirely on what “rarely makes mistakes” means.

    If the prediction is correct more than 50.05% of the time, then I would take the mystery box. Expected value = 0.5006 * 1,000,000 = 500,600

    If the prediction is correct less than 50.05% of the time, then I would take both: expected value = 1000 + (1 - 0.5004) * 1,000,000 = 500,600

    Since “rarely” usually means some value much less than 50%, I would definitely take the mystery box.