variouslegumes@reddthat.com to You Should Know@lemmy.world · 13 hours agoYSK about 15 bean soup.reddthat.comimagemessage-square96fedilinkarrow-up1186arrow-down16file-text
arrow-up1180arrow-down1imageYSK about 15 bean soup.reddthat.comvariouslegumes@reddthat.com to You Should Know@lemmy.world · 13 hours agomessage-square96fedilinkfile-text
minus-squareAbouBenAdhem@lemmy.worldlinkfedilinkEnglisharrow-up39·edit-29 hours agoWith an average-sized spoon, every spoonful could be a different type of 6 bean soup—it’s like getting five thousand soups in one!
minus-squareAtlas_@lemmy.worldlinkfedilinkarrow-up10·edit-27 hours ago15 choose 6 == 15 * 14 * 13 * 12 * 11 * 10 * 9/(6 * 5 * 4 * 3 * 2 * 1) == 5005 Wow, I did the math thinking, no, hoping you were wrong, but 5k is right on the money. You must have done the math. Good show sir
minus-squarebear@lemmy.blahaj.zonelinkfedilinkarrow-up1·4 hours agoWhy assume there are 6 beans in a spoonful? Maybe 15 choose 8 is a more common scoop… Assume no partial beans in spoonfuls. Also assume each bean type is as likely to be “scooped”. Finally, assume an infinitely large bowl of soup.
With an average-sized spoon, every spoonful could be a different type of 6 bean soup—it’s like getting five thousand soups in one!
15 choose 6 == 15 * 14 * 13 * 12 * 11 * 10 * 9/(6 * 5 * 4 * 3 * 2 * 1) == 5005
Wow, I did the math thinking, no, hoping you were wrong, but 5k is right on the money. You must have done the math. Good show sir
Why assume there are 6 beans in a spoonful? Maybe 15 choose 8 is a more common scoop… Assume no partial beans in spoonfuls. Also assume each bean type is as likely to be “scooped”. Finally, assume an infinitely large bowl of soup.