(I couldn’t find a sub for hypotethical questions…)

  • Ediacarium@feddit.org
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    2 days ago

    Once you’re able to use time as an information, they can send a message with a character limit. For every letter they need to wait:

    Remaining Message Length^Alphabet Size*Index of Letter*time interval

    So, if future people want to sent the message hello and our time unit is 1s, and the max message length is 5, they need to send the bit to exactly 26^4*7+26^3*4+26^2*11+26^1*11+26^0*14 = 3276872 seconds or 54614,5333min or 910,242222h or ~38 days after the start time.

    We can choose smaller time intervals, but with a long enough message, we’ll eventually reach the year 3000 again. Alternatively, we can move the start time into the past, at the expense of quite a few possible messages.

    This is the same problem as trying to map an n-dimensional array to a one dimensional array

      • Ediacarium@feddit.org
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        2 days ago

        If you’re not asking about anything that we currently don’t have a word for, we can use words as the alphabet, sure.

        We then need to transmit a list of words, they’re allowed to use, otherwise our count is off, because I’m sure that 974 years from now english won’t be the same, as it is today. They’ll have a lot more skibid rizz than we do now.

        • use Chinese xD

          logographic languages tend to last longer, especially now all the characters are digitized.

          A “Computer” didn’t exist in ancient times, but they still used words that have always existed to create new compound words: 电脑 (“Electric” + “Brain”). Airplanes didn’t exist but they still came up with the word 飞机 (“Flying” + “Machine”)

    • bacon_pdp@lemmy.world
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      2 days ago

      Wrong. Assuming 6bit encoding and one bit per minute; a 3 char start and stop sequence. 1024 character message could be sent per 4.3 days. Or a faster response time than my ex.

      • Hjalmar@feddit.nu
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        2 days ago

        You can’t send bits at a constant rate in this case. You essentialy get to send one very large number, the amount of time since your decided starting time (plus the one bit we were actually intended to use). The bit count grows logarithmicly with time

        Thus, the amount of bits n you can send over t time steps would be

        n = log(t)/log(2) + 1

        As an example, say they wait 8 seconds before sending you a 1. You have received the number 1000 and the bit 1. That’s a total of 5 bits.

        If they choose to wait twice as long, 16 seconds, they have in effect transmitted the numbers 10000 and one additional bit, a total of 6 bits. Double the time but only one additional bit.